MCQOPTIONS
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| 1. |
A ray of light is incident on the surface of a glass plate at an angle of incidence equal to Brewster's angle \[\varphi \]. If \[\mu \] represents the refractive index of glass with respect to air, then the angle between reflected and refracted rays is [CPMT 1989] |
| A. | \[90+\varphi \] |
| B. | \[{{\sin }^{-1}}(\mu \cos \varphi )\] |
| C. | 90o |
| D. | \[{{90}^{o}}-{{\sin }^{-1}}(\sin \varphi /\mu )\] |
| Answer» D. \[{{90}^{o}}-{{\sin }^{-1}}(\sin \varphi /\mu )\] | |