A proton (mass $$=1.67\times {{10}^{-27}}\,kg$$ and charge $$=1.6\times {{10}^{-19}}\,C)$$ enters perpendicular to a magnetic field of intensity 2 $$weber/{{m}^{2}}$$ with a velocity $$3.4\times {{10}^{7}}\,m/\sec $$. The acceleration of the proton should be [DPMT 1999]

Question

TuteeHUB · Accepted Answer

$$6.5\times {{10}^{13}}\,m/{{\sec }^{2}}$$

TuteeHUB · Answer

$$6.5\times {{10}^{15}}\,m/{{\sec }^{2}}$$

TuteeHUB · Answer

$$6.5\times {{10}^{13}}\,m/{{\sec }^{2}}$$

TuteeHUB · Answer

$$6.5\times {{10}^{11}}\,m/{{\sec }^{2}}$$

TuteeHUB · Answer

$$6.5\times {{10}^{9}}\,m/{{\sec }^{2}}$$

1.	A proton (mass \[=1.67\times {{10}^{-27}}\,kg\] and charge \[=1.6\times {{10}^{-19}}\,C)\] enters perpendicular to a magnetic field of intensity 2 \[weber/{{m}^{2}}\] with a velocity \[3.4\times {{10}^{7}}\,m/\sec \]. The acceleration of the proton should be [DPMT 1999]
A.	\[6.5\times {{10}^{15}}\,m/{{\sec }^{2}}\]
B.	\[6.5\times {{10}^{13}}\,m/{{\sec }^{2}}\]
C.	\[6.5\times {{10}^{11}}\,m/{{\sec }^{2}}\]
D.	\[6.5\times {{10}^{9}}\,m/{{\sec }^{2}}\]
Answer» B. \[6.5\times {{10}^{13}}\,m/{{\sec }^{2}}\]

A proton (mass \[=1.67\times {{10}^{-27}}\,kg\] and charge \[=1.6\times {{10}^{-19}}\,C)\] enters perpendicular to a magnetic field of intensity 2 \[weber/{{m}^{2}}\] with a velocity \[3.4\times {{10}^{7}}\,m/\sec \]. The acceleration of the proton should be [DPMT 1999]

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