A point O is the centre of a circle circumscribed about a triangle ABC. Then \[\overrightarrow{OA}\] sin 2A+\[\overrightarrow{OB}\] sin 2B + \[\overrightarrow{OC}\] sin 2C is equal to

\[(\overrightarrow{OA}+\overrightarrow{OB}+\overrightarrow{OC})sin2A\]

\[3\,\overrightarrow{OG}\], where G is the centroid of triangle ABC

A point O is the centre of a circle circumscribed about a triangle ABC

1.	A point O is the centre of a circle circumscribed about a triangle ABC. Then \[\overrightarrow{OA}\] sin 2A+\[\overrightarrow{OB}\] sin 2B + \[\overrightarrow{OC}\] sin 2C is equal to
A.	\[(\overrightarrow{OA}+\overrightarrow{OB}+\overrightarrow{OC})sin2A\]
B.	\[3\,\overrightarrow{OG}\], where G is the centroid of triangle ABC
C.	\[\overrightarrow{0}\]
D.	none of these
Answer» D. none of these

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A point O is the centre of a circle circumscribed about a triangle ABC. Then \[\overrightarrow{OA}\] sin 2A+\[\overrightarrow{OB}\] sin 2B + \[\overrightarrow{OC}\] sin 2C is equal to

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