MCQOPTIONS
Saved Bookmarks
MCQOPTIONS
| 1. |
A point mass oscillates along the x-axis according to the law\[x={{x}_{0}}\cos (\omega t-\pi /4)\]. If the acceleration of the particle is written as \[a=A\,\cos (\omega t+\delta )\], then |
| A. | \[A={{x}_{0}}{{\omega }^{2}},\,\delta =3\pi /4\] |
| B. | \[A={{x}_{0}},\,\delta =-\pi /4\] |
| C. | \[A={{x}_{0}}{{\omega }^{2}},\,\delta =\pi /4\] |
| D. | \[A={{x}_{0}}{{\omega }^{2}},\,\delta =-\pi /4\] |
| Answer» B. \[A={{x}_{0}},\,\delta =-\pi /4\] | |