A point dipole \(\vec p = - {p_0}\hat x\) is kept at the origin. The potential and electric field due to this dipole on the y -axis at a distance ‘d’ are, respectively: (Take V = 0 at infinity)

\(0,\frac{{\vec p}}{{4\pi {\epsilon_0}{{\rm{d}}^3}}}\)

\(\frac{{\left| {\vec p} \right|}}{{4\pi {\epsilon_0}{{\rm{d}}^2}}},\frac{{\vec p}}{{4\pi {\epsilon_0}{{\rm{d}}^3}}}\)

\(0,\frac{{ - \vec p}}{{4\pi {\epsilon_0}{{\rm{d}}^3}}}\)

\(\frac{{\left| {\vec p} \right|}}{{4\pi {\epsilon_0}{{\rm{d}}^2}}},\frac{{ - \vec p}}{{4\pi {\epsilon_0}{{\rm{d}}^3}}}\)

A point dipole \(\vec p = - {p_0}\hat x\) is kept at the origin. The

1.	A point dipole \(\vec p = - {p_0}\hat x\) is kept at the origin. The potential and electric field due to this dipole on the y -axis at a distance ‘d’ are, respectively: (Take V = 0 at infinity)
A.	\(\frac{{\left\| {\vec p} \right\|}}{{4\pi {\epsilon_0}{{\rm{d}}^2}}},\frac{{\vec p}}{{4\pi {\epsilon_0}{{\rm{d}}^3}}}\)
B.	\(0,\frac{{ - \vec p}}{{4\pi {\epsilon_0}{{\rm{d}}^3}}}\)
C.	\(0,\frac{{\vec p}}{{4\pi {\epsilon_0}{{\rm{d}}^3}}}\)
D.	\(\frac{{\left\| {\vec p} \right\|}}{{4\pi {\epsilon_0}{{\rm{d}}^2}}},\frac{{ - \vec p}}{{4\pi {\epsilon_0}{{\rm{d}}^3}}}\)
Answer» C. \(0,\frac{{\vec p}}{{4\pi {\epsilon_0}{{\rm{d}}^3}}}\)