A photon of frequency n causes photoelectric emission from a surface with threshold frequency \[{{n}_{0}}\].The de Broglie wavelength\[\lambda \]of the photoelectron emitted is given as

\[\Delta n=\frac{h}{2m\lambda }\]

\[\Delta n=\frac{h}{\lambda }\]

\[\left[ \frac{1}{{{v}_{0}}}-\frac{1}{v} \right]=\frac{m{{c}^{2}}}{h}\]

\[\lambda =\sqrt{\frac{h}{2m\Delta n}}\]

A photon of frequency n causes photoelectric emission from a surface w

1.	A photon of frequency n causes photoelectric emission from a surface with threshold frequency \[{{n}_{0}}\].The de Broglie wavelength\[\lambda \]of the photoelectron emitted is given as
A.	\[\Delta n=\frac{h}{2m\lambda }\]
B.	\[\Delta n=\frac{h}{\lambda }\]
C.	\[\left[ \frac{1}{{{v}_{0}}}-\frac{1}{v} \right]=\frac{m{{c}^{2}}}{h}\]
D.	\[\lambda =\sqrt{\frac{h}{2m\Delta n}}\]
Answer» E.

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A photon of frequency n causes photoelectric emission from a surface with threshold frequency \[{{n}_{0}}\].The de Broglie wavelength\[\lambda \]of the photoelectron emitted is given as

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