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| 1. |
A photon collides with a stationary hydrogen atom in ground state inelastically. Energy of the colliding photon is 10.2 eV. After a time interval of the order of micro second another photon collides with same hydrogen atom inelastically with an energy of 15 eV. What will be observed by the detector [IIT-JEE (Screening) 2005] |
| A. | 2 photon of energy 10.2 eV |
| B. | 2 photon of energy of 1.4 eV |
| C. | One photon of energy 10.2 eV and an electron of energy 1.4 eV |
| D. | One photon of energy 10.2 eV and another photon of 1.4 eV |
| Answer» D. One photon of energy 10.2 eV and another photon of 1.4 eV | |