A pendulum clock keeps correct time at \[0{}^\circ C\]. Its mean coefficient of linear expansions is a\[{{\alpha }^{o}}{{C}^{-1}}\]. The loss in seconds per day by the clock if the temperature rises by \[t{}^\circ C\] is

\[\frac{\frac{1}{2}\alpha \,t\times 86400}{{{\left( 1+\frac{\alpha \,t}{2} \right)}^{2}}}\]

\[\frac{\frac{1}{2}\alpha t\times 864000}{1-\frac{\alpha \,t}{2}}\]

\[\frac{1}{2}\alpha \,t\times 86400\]

\[\frac{\frac{1}{2}\alpha \,t\times 86400}{1+\frac{\alpha \,t}{2}}\]

A pendulum clock keeps correct time at \[0{}^\circ C\]. Its mean coeff

1.	A pendulum clock keeps correct time at \[0{}^\circ C\]. Its mean coefficient of linear expansions is a\[{{\alpha }^{o}}{{C}^{-1}}\]. The loss in seconds per day by the clock if the temperature rises by \[t{}^\circ C\] is
A.	\[\frac{\frac{1}{2}\alpha t\times 864000}{1-\frac{\alpha \,t}{2}}\]
B.	\[\frac{1}{2}\alpha \,t\times 86400\]
C.	\[\frac{\frac{1}{2}\alpha \,t\times 86400}{{{\left( 1+\frac{\alpha \,t}{2} \right)}^{2}}}\]
D.	\[\frac{\frac{1}{2}\alpha \,t\times 86400}{1+\frac{\alpha \,t}{2}}\]
Answer» C. \[\frac{\frac{1}{2}\alpha \,t\times 86400}{{{\left( 1+\frac{\alpha \,t}{2} \right)}^{2}}}\]