A particle of mass $${{m}_{1}}$$ is moving with a velocity $${{v}_{1}}$$and another particle of mass $${{m}_{2}}$$is moving with a velocity $${{v}_{2}}$$. Both of them have the same momentum but their different kinetic energies are $${{E}_{1}}$$and $${{E}_{2}}$$respectively. If $${{m}_{1}}{{m}_{2}}$$ then [CBSE PMT 2004]

Question

A particle of mass $${{m}_{1}}$$ is moving with a velocity $${{v}_{1}}$$and another particle of mass $${{m}_{2}}$$is moving with a velocity $${{v}_{2}}$$. Both of them have the same momentum but their different kinetic energies are $${{E}_{1}}$$and $${{E}_{2}}$$respectively. If $${{m}_{1}}>{{m}_{2}}$$ then                                            [CBSE PMT 2004]

TuteeHUB · Accepted Answer

$$\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{m}_{1}}}{{{m}_{2}}}$$

TuteeHUB · Answer

\[{{E}_{1}}

TuteeHUB · Answer

$${{E}_{1}}>{{E}_{2}}$$

TuteeHUB · Answer

$${{E}_{1}}={{E}_{2}}$$

1.	A particle of mass \[{{m}_{1}}\] is moving with a velocity \[{{v}_{1}}\]and another particle of mass \[{{m}_{2}}\]is moving with a velocity \[{{v}_{2}}\]. Both of them have the same momentum but their different kinetic energies are \[{{E}_{1}}\]and \[{{E}_{2}}\]respectively. If \[{{m}_{1}}>{{m}_{2}}\] then [CBSE PMT 2004]
A.	\[{{E}_{1}}<{{E}_{2}}\]
B.	\[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{m}_{1}}}{{{m}_{2}}}\]
C.	\[{{E}_{1}}>{{E}_{2}}\]
D.	\[{{E}_{1}}={{E}_{2}}\]
Answer» B. \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{m}_{1}}}{{{m}_{2}}}\]

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