A particle located in a one-dimensional potential field has its potent – McqOptions

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1.	A particle located in a one-dimensional potential field has its potential energy function as \[U(x)\,\frac{a}{{{x}^{4}}}-\frac{b}{{{x}^{2}}}\], where a and b are positive constants. The position of equilibrium x corresponds to
A.	\[\frac{b}{2a}\]
B.	\[\sqrt{\frac{2a}{b}}\]
C.	\[\sqrt{\frac{2a}{a}}\]
D.	\[\frac{a}{2a}\]
Answer» C. \[\sqrt{\frac{2a}{a}}\]

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