MCQOPTIONS
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| 1. |
A particle is thrown up inside a stationary lift of sufficient height. The time of flight is T. Now it is thrown again with same initial speed\[{{v}_{0}}\]with respect to lift. At the time of second throw, lift is moving up with speed \[{{v}_{0}}\] and uniform acceleration g upward (the acceleration due to gravity). The new time of flight is |
| A. | \[\sqrt{2T}\] |
| B. | \[\frac{T}{2}\] |
| C. | \[T\] |
| D. | \[2T\] |
| Answer» C. \[T\] | |