1.

A particle is projected with a velocity v such that its range on the horizontal plane is twice the greatest height attained by it. The range of the projectile is (where g is acceleration due to gravity)

A. \[\frac{4{{v}^{2}}}{5g}\]                    
B.        \[\frac{4g}{5{{v}^{2}}}\]
C. \[\frac{{{v}^{2}}}{g}\]                       
D.        \[\frac{4{{v}^{2}}}{\sqrt{5}g}\]
Answer» B.        \[\frac{4g}{5{{v}^{2}}}\]


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