MCQOPTIONS
Saved Bookmarks
| 1. |
A particle is projected with a certain velocity at an angle \[\alpha \] above the horizontal from the foot of an inclined plane of inclination\[30{}^\circ \]. If the particle strikes the plane normally, then \[\alpha \] is equal to |
| A. | \[30{}^\circ +\,te{{n}^{-1}}(\frac{\sqrt{3}}{2})\] |
| B. | \[45{}^\circ \] |
| C. | \[60{}^\circ \] |
| D. | \[30{}^\circ \,+\,te{{n}^{-1}}(2\sqrt{3})\] |
| Answer» B. \[45{}^\circ \] | |