1.

A parallel plate capacitor has capacitance C when no dielectric between the plates. Now a slab of dielectric constant K, having same thickness as the separation between the plates is introduced so as to fill one-fourth of the capacitor as shown in the figure. The new capacitance will be

A. \[(K+1)\frac{C}{4}\]     
B. \[(K+2)\frac{C}{4}\]
C. \[(K+3)\frac{C}{4}\]     
D. \[\frac{KC}{4}\]
Answer» D. \[\frac{KC}{4}\]


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