MCQOPTIONS
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| 1. |
A metal surface is illuminated by a light of given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one-fourth of its original value, then the maximum KE, of emitted photoelectrons will become |
| A. | (1/16)th of original value |
| B. | unchanged |
| C. | twice the original value |
| D. | four times the original value |
| Answer» C. twice the original value | |