1.

A man measures time period of a pendulum \[(T)\] in stationary lift. If the lift moves upward with acceleration \[\frac{g}{4},\] then new time period will be                           [BHU 2001]

A.             \[\frac{2T}{\sqrt{5}}\]
B.             \[\frac{\sqrt{5}T}{2}\]
C.             \[\frac{\sqrt{5}}{2T}\]           
D.             \[\frac{2}{\sqrt{5}T}\]
Answer» B.             \[\frac{\sqrt{5}T}{2}\]


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