1.

A man measures time period of a pendulum \[(T)\] in stationary lift. If the lift moves upward with acceleration \[\frac{g}{4},\] then new time period will be [BHU 2001]

A. \[\frac{2T}{\sqrt{5}}\]
B. \[\frac{\sqrt{5}T}{2}\]
C. \[\frac{\sqrt{5}}{2T}\]
D. \[\frac{2}{\sqrt{5}T}\]
Answer» B. \[\frac{\sqrt{5}T}{2}\]


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