MCQOPTIONS
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| 1. |
A man measures time period of a pendulum \[(T)\] in stationary lift. If the lift moves upward with acceleration \[\frac{g}{4},\] then new time period will be [BHU 2001] |
| A. | \[\frac{2T}{\sqrt{5}}\] |
| B. | \[\frac{\sqrt{5}T}{2}\] |
| C. | \[\frac{\sqrt{5}}{2T}\] |
| D. | \[\frac{2}{\sqrt{5}T}\] |
| Answer» B. \[\frac{\sqrt{5}T}{2}\] | |