1.

A man is standing between two parallel cliffs and fires a gun. If he hears first and second echoes after 1.5 s and 3.5s respectively, the distance between the cliffs is (Velocity of sound in air = 340 ms?1) [EAMCET (Med.) 2000]

A.   1190 m
B.   850 m
C.   595 m  
D.   510 m
Answer» C.   595 m  


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