MCQOPTIONS
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| 1. |
A man is standing between two parallel cliffs and fires a gun. If he hears first and second echoes after 1.5 s and 3.5s respectively, the distance between the cliffs is (Velocity of sound in air = 340 ms?1) [EAMCET (Med.) 2000] |
| A. | 1190 m |
| B. | 850 m |
| C. | 595 m |
| D. | 510 m |
| Answer» C. 595 m | |