MCQOPTIONS
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| 1. |
A hydrogen atom makes a transition from n=2 to n=1 and emits a photon. This photon strikes a doubly ionized lithium atom (z = 3) in excited state and completely removes the orbiting electron. The least quantum number for the excited state of the ion for the process is : |
| A. | 2 |
| B. | 4 |
| C. | 5 |
| D. | 3 |
| Answer» C. 5 | |