MCQOPTIONS
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MCQOPTIONS
| 1. |
A hydrogen atom in its ground state absorbs 10.2 eV of energy The orbital angular momentum is increased by |
| A. | \[1.05\times {{10}^{-34}}J-s\] |
| B. | \[3.16\times {{10}^{-34}}J-s\] [b] \[{{E}_{p}}=\frac{2{{K}_{ex}}}{{{\left( {{x}^{2}}+\frac{{{b}^{2}}}{4} \right)}^{3/2}}}\] For maximum \[{{E}_{p}}\] \[\frac{d{{E}_{p}}}{dx}=0\] \[\Rightarrow x=\frac{b}{2\sqrt{2}}\] |
| C. | \[2.11\times {{10}^{-34}}J-s\] |
| D. | \[4.22\times {{10}^{-34}}J-s\] |
| Answer» B. \[3.16\times {{10}^{-34}}J-s\] [b] \[{{E}_{p}}=\frac{2{{K}_{ex}}}{{{\left( {{x}^{2}}+\frac{{{b}^{2}}}{4} \right)}^{3/2}}}\] For maximum \[{{E}_{p}}\] \[\frac{d{{E}_{p}}}{dx}=0\] \[\Rightarrow x=\frac{b}{2\sqrt{2}}\] | |