A frictionless dielectric plate $$S$$ is kept on a frictionless table $$T$$. A charged parallel plate capacitance $$C$$ (of which the plates are frictionless) is kept near it. The plate $$S$$ is between the plates. When the plate $$S$$ is left between the plates [CPMT 1988]

Question

A frictionless dielectric plate $$S$$ is kept on a frictionless table $$T$$. A charged parallel plate capacitance $$C$$ (of which the plates are frictionless) is kept near it. The plate $$S$$ is between the plates. When the plate $$S$$ is left between the plates                                                               [CPMT 1988]

TuteeHUB · Accepted Answer

All the above statements are false

TuteeHUB · Answer

It will remain stationary on the table

TuteeHUB · Answer

It is pulled by the capacitor and will pass on the other end

TuteeHUB · Answer

It is pulled between the plates and will remain there

1.	A frictionless dielectric plate \[S\] is kept on a frictionless table \[T\]. A charged parallel plate capacitance \[C\] (of which the plates are frictionless) is kept near it. The plate \[S\] is between the plates. When the plate \[S\] is left between the plates [CPMT 1988]
A.	It will remain stationary on the table
B.	It is pulled by the capacitor and will pass on the other end
C.	It is pulled between the plates and will remain there
D.	All the above statements are false
Answer» D. All the above statements are false

A frictionless dielectric plate \[S\] is kept on a frictionless table \[T\]. A charged parallel plate capacitance \[C\] (of which the plates are frictionless) is kept near it. The plate \[S\] is between the plates. When the plate \[S\] is left between the plates [CPMT 1988]

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