A force $$F$$ acts between sodium and chlorine ions of salt (sodium chloride) when put $$1\,cm$$ apart in air. The permittivity of air and dielectric constant of water are $${{\varepsilon }_{0}}$$ and $$K$$ respectively. When a piece of salt is put in water electrical force acting between sodium and chlorine ions $$1\,cm$$ apart is [MP PET 1995]

Question

A force $$F$$ acts between sodium and chlorine ions of salt (sodium chloride) when put $$1\,cm$$ apart in air. The permittivity of air and dielectric constant of water are $${{\varepsilon }_{0}}$$ and $$K$$ respectively. When a piece of salt is put in water electrical force acting between sodium and chlorine ions $$1\,cm$$ apart is          [MP PET 1995]

TuteeHUB · Accepted Answer

$$\frac{FK}{{{\varepsilon }_{0}}}$$

TuteeHUB · Answer

$$\frac{F}{K}$$

TuteeHUB · Answer

$$\frac{F}{K{{\varepsilon }_{0}}}$$

TuteeHUB · Answer

$$\frac{F{{\varepsilon }_{0}}}{K}$$

1.	A force \[F\] acts between sodium and chlorine ions of salt (sodium chloride) when put \[1\,cm\] apart in air. The permittivity of air and dielectric constant of water are \[{{\varepsilon }_{0}}\] and \[K\] respectively. When a piece of salt is put in water electrical force acting between sodium and chlorine ions \[1\,cm\] apart is [MP PET 1995]
A.	\[\frac{F}{K}\]
B.	\[\frac{FK}{{{\varepsilon }_{0}}}\]
C.	\[\frac{F}{K{{\varepsilon }_{0}}}\]
D.	\[\frac{F{{\varepsilon }_{0}}}{K}\]
Answer» B. \[\frac{FK}{{{\varepsilon }_{0}}}\]

Discussion

No Comment Found

Related MCQs

Reply to Comment