MCQOPTIONS
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| 1. |
A force acts on a 30 gm particle in such a way that the position of the particle as a function of time is given by \[x=3t-4{{t}^{2}}+{{t}^{3}}\], where x is in metres and t is in seconds. The work done during the first 4 seconds is [CBSE PMT 1998] |
| A. | 5.28 J |
| B. | 450 mJ |
| C. | 490 mJ |
| D. | 530 mJ |
| Answer» B. 450 mJ | |