1.

A force acts on a 30 gm particle in such a way that the position of the particle as a function of time is given by \[x=3t-4{{t}^{2}}+{{t}^{3}}\], where x is in metres and t is in seconds. The work done during the first 4 seconds is           [CBSE PMT 1998]

A. 5.28 J
B. 450 mJ
C. 490 mJ
D. 530 mJ
Answer» B. 450 mJ


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