A fair coin it tossed 2n times. The probability of getting as many heads in the first n tosses as in the last n is

\[\frac{^{2n}{{C}_{n-1}}}{{{2}^{n}}}\]

\[\frac{^{2n}{{C}_{n}}}{{{2}^{2n}}}\]

A fair coin it tossed 2n times. The probability of getting as many hea

1.	A fair coin it tossed 2n times. The probability of getting as many heads in the first n tosses as in the last n is
A.	\[\frac{^{2n}{{C}_{n}}}{{{2}^{2n}}}\]
B.	\[\frac{^{2n}{{C}_{n-1}}}{{{2}^{n}}}\]
C.	\[\frac{n}{{{2}^{2n}}}\]
D.	None
Answer» B. \[\frac{^{2n}{{C}_{n-1}}}{{{2}^{n}}}\]

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A fair coin it tossed 2n times. The probability of getting as many heads in the first n tosses as in the last n is

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