A dye absorbs a photon of wavelength \[\lambda \] and re-emits the same energy into two photons of wavelength \[{{\lambda }_{1}}\] and \[{{\lambda }_{2}}\] respectively. The wavelength \[\lambda \] is related with \[{{\lambda }_{1}}\] and \[{{\lambda }_{2}}\] as:

\[\lambda =\frac{{{\lambda }_{1}}^{2}{{\lambda }_{2}}^{2}}{{{\lambda }_{1}}+{{\lambda }_{2}}}\]

\[\lambda =\frac{{{\lambda }_{1}}+{{\lambda }_{2}}}{{{\lambda }_{1}}{{\lambda }_{2}}}\]

\[\lambda =\frac{{{\lambda }_{1}}{{\lambda }_{2}}}{{{\lambda }_{1}}+{{\lambda }_{2}}}\]

\[\lambda =\frac{{{\lambda }_{1}}{{\lambda }_{2}}}{{{({{\lambda }_{1}}+{{\lambda }_{2}})}^{2}}}\]

A dye absorbs a photon of wavelength \[\lambda \] and re-emits the sam

1.	A dye absorbs a photon of wavelength \[\lambda \] and re-emits the same energy into two photons of wavelength \[{{\lambda }_{1}}\] and \[{{\lambda }_{2}}\] respectively. The wavelength \[\lambda \] is related with \[{{\lambda }_{1}}\] and \[{{\lambda }_{2}}\] as:
A.	\[\lambda =\frac{{{\lambda }_{1}}+{{\lambda }_{2}}}{{{\lambda }_{1}}{{\lambda }_{2}}}\]
B.	\[\lambda =\frac{{{\lambda }_{1}}{{\lambda }_{2}}}{{{\lambda }_{1}}+{{\lambda }_{2}}}\]
C.	\[\lambda =\frac{{{\lambda }_{1}}^{2}{{\lambda }_{2}}^{2}}{{{\lambda }_{1}}+{{\lambda }_{2}}}\]
D.	\[\lambda =\frac{{{\lambda }_{1}}{{\lambda }_{2}}}{{{({{\lambda }_{1}}+{{\lambda }_{2}})}^{2}}}\]
Answer» C. \[\lambda =\frac{{{\lambda }_{1}}^{2}{{\lambda }_{2}}^{2}}{{{\lambda }_{1}}+{{\lambda }_{2}}}\]

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A dye absorbs a photon of wavelength \[\lambda \] and re-emits the same energy into two photons of wavelength \[{{\lambda }_{1}}\] and \[{{\lambda }_{2}}\] respectively. The wavelength \[\lambda \] is related with \[{{\lambda }_{1}}\] and \[{{\lambda }_{2}}\] as:

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