1.

A deutron of kinetic energy 50 keV is describing a circular orbit of radius 0.5 metre in a plane perpendicular to magnetic field \[\overrightarrow{B}\]. The kinetic energy of the proton that describes a circular orbit of radius 0.5 metre in the same plane with the same \[\overrightarrow{B}\] is                                        [CBSE PMT 1991]

A.            25 keV                                     
B.            50 keV
C.            200 keV                                  
D.            100 keV
Answer» E.


Discussion

No Comment Found

Related MCQs