A deuteron of kinetic energy 50 ke V is describing a circular orbit of – McqOptions

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1.	A deuteron of kinetic energy 50 ke V is describing a circular orbit of radius 0.5 metre in a plane perpendicular to the magnetic field B. The kinetic energy of the proton that describes a circular orbit of radius 0.5 metre in the same plane with the same B is
A.	\[25\,ke\,V\]
B.	\[50\,ke\,V\]
C.	\[200\,ke\,V\]
D.	\[100\,ke\,V\]
Answer» E.

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