A curve passing through (2, 3) and satisfying the differential equation \[\int_{0}^{x}{ty(t)dt={{x}^{2}}y(x),(x>0)}\] is

\[\frac{{{x}^{2}}}{8}+\frac{{{y}^{2}}}{18}=1\]

A curve passing through (2, 3) and satisfying the differential equatio

1.	A curve passing through (2, 3) and satisfying the differential equation \[\int_{0}^{x}{ty(t)dt={{x}^{2}}y(x),(x>0)}\] is
A.	\[{{x}^{2}}+{{y}^{2}}=13\]
B.	\[{{y}^{2}}=\frac{9}{2}x\]
C.	\[\frac{{{x}^{2}}}{8}+\frac{{{y}^{2}}}{18}=1\]
D.	\[xy=c\]
Answer» E.

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A curve passing through (2, 3) and satisfying the differential equation \[\int_{0}^{x}{ty(t)dt={{x}^{2}}y(x),(x>0)}\] is

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