A current carrying coil is placed with its axis perpendicular to N-S direction. Let horizontal component of earth's magnetic field be $${{H}_{0}}$$ and magnetic field inside the loop be H. If a magnet is suspended inside the loop, it makes angle $$\theta $$ with H. Then $$\theta $$=

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TuteeHUB · Accepted Answer

$${{\tan }^{-1}}\left( \frac{H}{{{H}_{0}}} \right)$$

TuteeHUB · Answer

$${{\tan }^{-1}}\left( \frac{{{H}_{0}}}{H} \right)$$

TuteeHUB · Answer

$$\cos e{{c}^{-1}}\left( \frac{H}{{{H}_{0}}} \right)$$

TuteeHUB · Answer

$${{\cot }^{-1}}\left( \frac{{{H}_{0}}}{H} \right)$$

1.	A current carrying coil is placed with its axis perpendicular to N-S direction. Let horizontal component of earth's magnetic field be \[{{H}_{0}}\] and magnetic field inside the loop be H. If a magnet is suspended inside the loop, it makes angle \[\theta \] with H. Then \[\theta \]=
A.	\[{{\tan }^{-1}}\left( \frac{{{H}_{0}}}{H} \right)\]
B.	\[{{\tan }^{-1}}\left( \frac{H}{{{H}_{0}}} \right)\]
C.	\[\cos e{{c}^{-1}}\left( \frac{H}{{{H}_{0}}} \right)\]
D.	\[{{\cot }^{-1}}\left( \frac{{{H}_{0}}}{H} \right)\]
Answer» B. \[{{\tan }^{-1}}\left( \frac{H}{{{H}_{0}}} \right)\]

A current carrying coil is placed with its axis perpendicular to N-S direction. Let horizontal component of earth's magnetic field be \[{{H}_{0}}\] and magnetic field inside the loop be H. If a magnet is suspended inside the loop, it makes angle \[\theta \] with H. Then \[\theta \]=

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