A composite slab has two layers of different materials having internal conductivities, k1 and k2. If each layer has the same thickness, then what is the equivalent thermal conductivity of the slab?

\(\frac {k_1 k_2}{2(k_1 + k_2)}\)

\(\frac {2k_1 k_2}{k_1 + k_2}\)

A composite slab has two layers of different materials having internal

1.	A composite slab has two layers of different materials having internal conductivities, k1 and k2. If each layer has the same thickness, then what is the equivalent thermal conductivity of the slab?
A.	\(\frac {k_1 k_2}{k_1 + k_2}\)
B.	\(\frac {k_1 k_2}{2(k_1 + k_2)}\)
C.	\(\frac {2k_1 }{k_1 + k_2}\)
D.	\(\frac {2k_1 k_2}{k_1 + k_2}\)
Answer» E.

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A composite slab has two layers of different materials having internal conductivities, k1 and k2. If each layer has the same thickness, then what is the equivalent thermal conductivity of the slab?

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