A circle passes through the origin and has its centre on \[y=x\]. If it cuts \[{{x}^{2}}+{{y}^{2}}-4x-6y+10=0\] orthogonally, then the equation of the circle is [EAMCET 1994]

\[{{x}^{2}}+{{y}^{2}}+2x+2y=0\]

\[{{x}^{2}}+{{y}^{2}}-6x-4y=0\]

\[{{x}^{2}}+{{y}^{2}}-2x-2y=0\]

A circle passes through the origin and has its centre on \[y=x\]. If i

1.	A circle passes through the origin and has its centre on \[y=x\]. If it cuts \[{{x}^{2}}+{{y}^{2}}-4x-6y+10=0\] orthogonally, then the equation of the circle is [EAMCET 1994]
A.	\[{{x}^{2}}+{{y}^{2}}-x-y=0\]
B.	\[{{x}^{2}}+{{y}^{2}}-6x-4y=0\]
C.	\[{{x}^{2}}+{{y}^{2}}-2x-2y=0\]
D.	\[{{x}^{2}}+{{y}^{2}}+2x+2y=0\]
Answer» D. \[{{x}^{2}}+{{y}^{2}}+2x+2y=0\]

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A circle passes through the origin and has its centre on \[y=x\]. If it cuts \[{{x}^{2}}+{{y}^{2}}-4x-6y+10=0\] orthogonally, then the equation of the circle is [EAMCET 1994]

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