A circle is concentric with the circle \[{{x}^{2}}+{{y}^{2}}-6x+12y+15=0\] and has area double of its area. The equation of the circle is

\[{{x}^{2}}+{{y}^{2}}-6x+12y+15=0\]

\[{{x}^{2}}+{{y}^{2}}-6x+12y-15=0\]

\[{{x}^{2}}+{{y}^{2}}-6x+12y+45=0\]

A circle is concentric with the circle \[{{x}^{2}}+{{y}^{2}}-6x+12y+15

1.	A circle is concentric with the circle \[{{x}^{2}}+{{y}^{2}}-6x+12y+15=0\] and has area double of its area. The equation of the circle is
A.	\[{{x}^{2}}+{{y}^{2}}-6x+12y-15=0\]
B.	\[{{x}^{2}}+{{y}^{2}}-6x+12y+15=0\]
C.	\[{{x}^{2}}+{{y}^{2}}-6x+12y+45=0\]
D.	None of these
Answer» B. \[{{x}^{2}}+{{y}^{2}}-6x+12y+15=0\]

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A circle is concentric with the circle \[{{x}^{2}}+{{y}^{2}}-6x+12y+15=0\] and has area double of its area. The equation of the circle is

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