MCQOPTIONS
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| 1. |
A circle has radius 3 units and its centre lies on the line \[y=x-1\]. Then the equation of this circle if it passes through point (7,3), is [Roorkee 1988] |
| A. | \[{{x}^{2}}+{{y}^{2}}-8x-6y+16=0\] |
| B. | \[{{x}^{2}}+{{y}^{2}}+8x+6y+16=0\] |
| C. | \[{{x}^{2}}+{{y}^{2}}-8x-6y-16=0\] |
| D. | None of these |
| Answer» B. \[{{x}^{2}}+{{y}^{2}}+8x+6y+16=0\] | |