A charged particle is suspended in equilibrium in a uniform vertical electric field of intensity 20000 V/m. If mass of the particle is $$9.6\times {{10}^{-16}}\,kg$$, the charge on it and excess number of electrons on the particle are respectively $$(g=10\,m/{{s}^{2}})$$ [Pb. PMT 2003]

Question

A charged particle is suspended in equilibrium in a uniform vertical electric field of intensity 20000 V/m. If mass of the particle is $$9.6\times {{10}^{-16}}\,kg$$, the charge on it and excess number of electrons on the particle are respectively $$(g=10\,m/{{s}^{2}})$$                                                                                   [Pb. PMT 2003]

TuteeHUB · Accepted Answer

$$2.8\times {{10}^{-19}}C,\,1$$

TuteeHUB · Answer

$$4.8\times {{10}^{-19}}C,\,3$$

TuteeHUB · Answer

$$5.8\times {{10}^{-19}}C,\,4$$

TuteeHUB · Answer

$$3.8\times {{10}^{-19}}C,\,2$$

1.	A charged particle is suspended in equilibrium in a uniform vertical electric field of intensity 20000 V/m. If mass of the particle is \[9.6\times {{10}^{-16}}\,kg\], the charge on it and excess number of electrons on the particle are respectively \[(g=10\,m/{{s}^{2}})\] [Pb. PMT 2003]
A.	\[4.8\times {{10}^{-19}}C,\,3\]
B.	\[5.8\times {{10}^{-19}}C,\,4\]
C.	\[3.8\times {{10}^{-19}}C,\,2\]
D.	\[2.8\times {{10}^{-19}}C,\,1\]
Answer» D. \[2.8\times {{10}^{-19}}C,\,1\]

A charged particle is suspended in equilibrium in a uniform vertical electric field of intensity 20000 V/m. If mass of the particle is \[9.6\times {{10}^{-16}}\,kg\], the charge on it and excess number of electrons on the particle are respectively \[(g=10\,m/{{s}^{2}})\] [Pb. PMT 2003]

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