A car, starting from rest, accelerates at the rate through a distance S, then continues at constant speed for time t and then decelerates at the rate \[\frac{\text{f}}{2}\]to come to rest. If the total distance traversed is 15 S, then

\[\text{S=}\frac{\text{1}}{\text{6}}\text{f}{{\text{t}}^{\text{2}}}\]

\[\text{S=}\frac{\text{1}}{\text{4}}\text{f}{{\text{t}}^{\text{2}}}\]

\[\text{S=}\frac{\text{1}}{\text{72}}\text{f}{{\text{t}}^{\text{2}}}\]

A car, starting from rest, accelerates at the rate through a distance

1.	A car, starting from rest, accelerates at the rate through a distance S, then continues at constant speed for time t and then decelerates at the rate \[\frac{\text{f}}{2}\]to come to rest. If the total distance traversed is 15 S, then
A.	\[\text{S=}\frac{\text{1}}{\text{6}}\text{f}{{\text{t}}^{\text{2}}}\]
B.	\[\text{S=ft}\]
C.	\[\text{S=}\frac{\text{1}}{\text{4}}\text{f}{{\text{t}}^{\text{2}}}\]
D.	\[\text{S=}\frac{\text{1}}{\text{72}}\text{f}{{\text{t}}^{\text{2}}}\]
Answer» E.