A boy increases his speed to \(\frac{9}{5}\) times of his original speed. By doing this, he reaches his school 40 minutes before the usual time. How much time (in minutes) does he take usually?

A boy increases his speed to \(\frac{9}{5}\) times of his original sp

1.	A boy increases his speed to \(\frac{9}{5}\) times of his original speed. By doing this, he reaches his school 40 minutes before the usual time. How much time (in minutes) does he take usually?
A.	120
B.	30
C.	45
D.	90
Answer» E.

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A boy increases his speed to \(\frac{9}{5}\) times of his original speed. By doing this, he reaches his school 40 minutes before the usual time. How much time (in minutes) does he take usually?

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