A box containing 4 white pens and 2 black pens. Another box containing 3 white pens and 5 black pens. If one pen is selected from each box, then the probability that both the pens are white is equal to [Pb.CET 2002]

A box containing 4 white pens and 2 black pens. Another box containing

1.	A box containing 4 white pens and 2 black pens. Another box containing 3 white pens and 5 black pens. If one pen is selected from each box, then the probability that both the pens are white is equal to [Pb.CET 2002]
A.	\[\frac{1}{2}\]
B.	\[\frac{1}{3}\]
C.	\[\frac{1}{4}\]
D.	\[\frac{1}{5}\]
Answer» D. \[\frac{1}{5}\]

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A box containing 4 white pens and 2 black pens. Another box containing 3 white pens and 5 black pens. If one pen is selected from each box, then the probability that both the pens are white is equal to [Pb.CET 2002]

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