MCQOPTIONS
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| 1. |
A body thrown vertically so as to reach its maximum height in t second. The total time from the time of projection to reach a point at half of its maximum height while returning (in sec) is |
| A. | \[\sqrt{\text{2}}\text{t}\] |
| B. | \[\left( \text{1+}\frac{\text{1}}{\sqrt{\text{2}}} \right)\text{t}\] |
| C. | \[\frac{\text{3t}}{\text{2}}\] |
| D. | \[\frac{\text{t}}{\sqrt{\text{2}}}\] |
| Answer» C. \[\frac{\text{3t}}{\text{2}}\] | |