1.

A body thrown vertically so as to reach its maximum height in t second. The total time from the time of projection to reach a point at half of its maximum height while returning (in sec) is

A. \[\sqrt{\text{2}}\text{t}\]           
B. \[\left( \text{1+}\frac{\text{1}}{\sqrt{\text{2}}} \right)\text{t}\]
C. \[\frac{\text{3t}}{\text{2}}\]                  
D. \[\frac{\text{t}}{\sqrt{\text{2}}}\]
Answer» C. \[\frac{\text{3t}}{\text{2}}\]                  


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