MCQOPTIONS
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| 1. |
A body is released from the top of a tower of height \[h\]. It takes \[v=\frac{1}{2}b{{t}^{2}}+{{v}_{0}}\] sec to reach the ground. Where will be the ball after time \[t/2\] sec [NCERT 1981; MP PMT 2004] |
| A. | At \[h/2\]from the ground |
| B. | At \[h/4\] from the ground |
| C. | Depends upon mass and volume of the body |
| D. | At \[3h/4\] from the ground |
| Answer» E. | |