MCQOPTIONS
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| 1. |
A body A is thrown vertically upward with the initial velocity \[{{v}_{1}}\]. Another body B is dropped from a height h. Find how the distance x between the bodies depends on the time t if the bodies begin to move simultaneously. |
| A. | \[x=h-{{v}_{1}}t\] |
| B. | \[x=\left( h-{{v}_{1}} \right)t\] |
| C. | \[x=h-\frac{{{v}_{1}}}{t}\] |
| D. | \[x=\frac{h}{t}-{{v}_{1}}\] |
| Answer» B. \[x=\left( h-{{v}_{1}} \right)t\] | |