A block of mass M is released from point P on a rough inclined plane with an inclination angle θ, shown in the figure below. The coefficient of friction is μ. If μ < tan θ, then the time taken by the block to reach another point Q on the inclined plane, where PQ = S, is

\(\sqrt {\frac{{2s}}{{g\cos \theta \left( {\tan \theta + \mu } \right)}}} \)

\(\sqrt {\frac{{2s}}{{g\cos \theta \left( {\tan \theta - \mu } \right)}}} \)

\(\sqrt {\frac{{2s}}{{g\sin \theta \left( {\tan \theta - \mu } \right)}}} \)

\(\sqrt {\frac{{2s}}{{g\sin \theta \left( {\tan \theta + \mu } \right)}}} \)

A block of mass M is released from point P on a rough inclined plane w

1.	A block of mass M is released from point P on a rough inclined plane with an inclination angle θ, shown in the figure below. The coefficient of friction is μ. If μ < tan θ, then the time taken by the block to reach another point Q on the inclined plane, where PQ = S, is
A.	\(\sqrt {\frac{{2s}}{{g\cos \theta \left( {\tan \theta - \mu } \right)}}} \)
B.	\(\sqrt {\frac{{2s}}{{g\cos \theta \left( {\tan \theta + \mu } \right)}}} \)
C.	\(\sqrt {\frac{{2s}}{{g\sin \theta \left( {\tan \theta - \mu } \right)}}} \)
D.	\(\sqrt {\frac{{2s}}{{g\sin \theta \left( {\tan \theta + \mu } \right)}}} \)
Answer» B. \(\sqrt {\frac{{2s}}{{g\cos \theta \left( {\tan \theta + \mu } \right)}}} \)

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A block of mass M is released from point P on a rough inclined plane with an inclination angle θ, shown in the figure below. The coefficient of friction is μ. If μ < tan θ, then the time taken by the block to reach another point Q on the inclined plane, where PQ = S, is

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