A block of 500 N is to be moved upward for a distance of 1.6 m on an inclined plane of 45° with horizontal. Work done will be [μ = 0.25]:

A block of 500 N is to be moved upward for a distance of 1.6 m on an i

1.	A block of 500 N is to be moved upward for a distance of 1.6 m on an inclined plane of 45° with horizontal. Work done will be [μ = 0.25]:
A.	1000 Nm
B.	500√2 Nm
C.	500 Nm
D.	100 Nm
Answer» C. 500 Nm

Discussion

No Comment Found

Related MCQs

Determine the nature of force in member AB and AC respectively of the truss shown in figure. A is hinge support and B is roller support. The direction of reaction at supports (RA and RB) is also shown. Load 50 N is acting at joint C.
If two forces each equal top act at right angles, their effect may be neutralized by a third force acting along their bisector in opposite direction whose magnitude is equal to
A circular disc rolls down an inclined plane, the fraction of its total energy associated with its rotation is _____.
A block weighing 981 N is resting on a horizontal surface. The coefficient of friction between the block and the horizontal surface is μ = 0.2. A vertical cable attached to the block provides partial support as shown. A man can pull horizontally with a force of 100 N. What will be the tension, T (in N) in the cable if the man is just able to move the block to the right?
A block of mass 4√2 kg is at rest on the inclined plane. The inclined plane is inclined at an angle of 135° from horizontal direction in anticlockwise direction. Determine the coefficient of friction so that block can start slide in downward direction, assume the acceleration of gravity as 10 m/s2.
A 13 m ladder is placed against a smooth vertical wall with its lower end 5 m from the wall. What should be the coefficient of friction between the ladder and floor so that it remains in equilibrium?
A cylinder of radius 250 mm and weight, W = 10 kN is rolled up an obstacle of height 50 mm by applying a horizontal force P at its center as shown in the figure.All interfaces are assumed frictionless. The minimum value of P is
A beam is subjected to a force system shown in figure. This force system can be reduced to:
Let F1 and F2 be the force between two bodies separated by a distance d and 2d respectively. Then F2/F1 is
In collinear force system the forces whose line of action lie on:

A block of 500 N is to be moved upward for a distance of 1.6 m on an inclined plane of 45° with horizontal. Work done will be [μ = 0.25]:

Discussion

No Comment Found

Related MCQs

Reply to Comment