A beam of light is converging towards a point $$I$$ on a screen. A plane glass plate whose thickness in the direction of the beam = $$t$$, refractive index = $$\mu $$, is introduced in the path of the beam. The convergence point is shifted by [MNR 1987]

Question

TuteeHUB · Accepted Answer

$$t\,\left( 1+\frac{1}{\mu } \right)$$ away

TuteeHUB · Answer

$$t\,\left( 1-\frac{1}{\mu } \right)$$ away

TuteeHUB · Answer

$$t\,\left( 1+\frac{1}{\mu } \right)$$ away

TuteeHUB · Answer

$$t\,\left( 1-\frac{1}{\mu } \right)$$ nearer

TuteeHUB · Answer

$$t\,\left( 1+\frac{1}{\mu } \right)$$ nearer

1.	A beam of light is converging towards a point \[I\] on a screen. A plane glass plate whose thickness in the direction of the beam = \[t\], refractive index = \[\mu \], is introduced in the path of the beam. The convergence point is shifted by [MNR 1987]
A.	\[t\,\left( 1-\frac{1}{\mu } \right)\] away
B.	\[t\,\left( 1+\frac{1}{\mu } \right)\] away
C.	\[t\,\left( 1-\frac{1}{\mu } \right)\] nearer
D.	\[t\,\left( 1+\frac{1}{\mu } \right)\] nearer
Answer» B. \[t\,\left( 1+\frac{1}{\mu } \right)\] away

A beam of light is converging towards a point \[I\] on a screen. A plane glass plate whose thickness in the direction of the beam = \[t\], refractive index = \[\mu \], is introduced in the path of the beam. The convergence point is shifted by [MNR 1987]

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