A bag has four cuboids and three cubes. What is probability of getting

1.	A bag has four cuboids and three cubes. What is probability of getting 1 cube ?
A.	3/7
B.	4/7
C.	1
D.	2/7
Answer» B. 4/7

Discussion

No Comment Found

Related MCQs

In a class of 60 students, 40 opted for NCC, 30 opted for NSS and 20 opted for both NCC and NSS. If one of these students is selected at random, then the probability that the student selected has opted neither for NCC nor for NSS is
In a multiple-choice test, an examinee either knows the correct answer with probability p, or guesses with probability 1 - p. The probability of answering a question correctly is , if he or she merely guesses. If the examinee answers a question correctly, the probability that he or she really knows the answer is
Eight coins are tossed 25,600 times. The average number of eight heads is
Consider the following statements:1) P(A̅ ∪ B) = P(A̅) + P (B) – P(A̅ ∩ B)2) P(A ∪ B̅ ) = P(B) – P(A ∩ B)3) P(A ∩ B) = P(B) P(A|B)Which of the above statements are correct?
If x ∈ [0, 5], then what is the probability that x2 - 3x + 2 ≥ 0?
A random variable is known to have a cumulative distribution function \(F_X (x)=U(x)(1-\frac{x^2}{b})\). Its density function is:
A bag contains 4 blue, 3 green, 3 white and 5 black marbles. If four marbles are picked at random, what is the probability of at least one being blue?
In a Binomial distribution, the mean is three times its variance. What is the probability of exactly 3 successes out of 5 trials?
If A and B are two events such that P(A) = 0.6, P(B) = 0.5 and P(A ∩ B) = 0.4, then consider the following statements:1. P(A̅ ∪ B) = 0.92. P(B̅ | A̅) = 0.6Which of the statements is / are correct?
A bag contains X red balls and 5 green balls. 2 balls are picked up from the bag at random, one after the other, without replacement, the probability of both balls being red is 3/7. What will be the value of X?

A bag has four cuboids and three cubes. What is probability of getting 1 cube ?

Discussion

No Comment Found

Related MCQs

Reply to Comment