A bag contains 4 red, 5 white and 6 black balls. Three balls are drawn WITHOUT replacement. What is the probability that the three drawn balls are black?

A bag contains 4 red, 5 white and 6 black balls. Three balls are drawn

1.	A bag contains 4 red, 5 white and 6 black balls. Three balls are drawn WITHOUT replacement. What is the probability that the three drawn balls are black?
A.	\(\dfrac{4}{91}\)
B.	\(\dfrac{2}{5}\)
C.	\(\dfrac{1}{5}\)
D.	\(\dfrac{6}{91}\)
Answer» B. \(\dfrac{2}{5}\)

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A bag contains 4 red, 5 white and 6 black balls. Three balls are drawn WITHOUT replacement. What is the probability that the three drawn balls are black?

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