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 A and B can do a job together in 7 days. A is 13/4 times as efficient as B. The same job can be done by A alone in

A. (A's 1 day's work) : (B's 1 day's work) = 7/4 : 1   =   7 : 4.
B. Let A's and B's 1 day's work be 7x and 4x respectively.
C. Then, 7x + 4x = 1/7     =>     11x = 1/7     =>     x = 1/77 .
D. Therefore A's 1 day's work = ( 1/77 x 7 ) = 1/11  = 11 days
Answer» B. Let A's and B's 1 day's work be 7x and 4x respectively.


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