MCQOPTIONS
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| 1. |
A 10 cm long bar magnet of magnetic moment \[1.34\,A{{m}^{2}}\] is placed in the magnetic meridian with its south pole pointing geographical south. The neutral point is obtained at a distance of 15 cm from the centre of the magnet. Calculate the horizontal component of earth's magnetic field. |
| A. | \[0.12\times {{10}^{-4}}\,T\] |
| B. | \[0.21\times {{10}^{-4}}T\] |
| C. | \[0.34\times {{10}^{-4}}T\] |
| D. | \[0.87\times {{10}^{-7}}T\] |
| Answer» D. \[0.87\times {{10}^{-7}}T\] | |