A 0.001 molal solution of\[[Pt{{(N{{H}_{3}})}_{4}}C{{l}_{4}}]\] in wat – McqOptions

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1.	A 0.001 molal solution of\[[Pt{{(N{{H}_{3}})}_{4}}C{{l}_{4}}]\] in water had a freezing point depression of\[0.0054{}^\circ C\]. If \[{{K}_{f}}\] for water is 1.80, the correct formulation for the above molecule is
A.	\[[Pt{{(N{{H}_{3}})}_{4}}C{{l}_{3}}]Cl\]
B.	\[[Pt{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]C{{l}_{2}}\]
C.	\[[Pt{{(N{{H}_{3}})}_{4}}Cl]C{{l}_{3}}\]
D.	\[[Pt{{(N{{H}_{3}})}_{4}}C{{l}_{4}}]\]
Answer» C. \[[Pt{{(N{{H}_{3}})}_{4}}Cl]C{{l}_{3}}\]

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