. 8x2 + 6x = 5 . 12y2 22y + 8 = 0 – McqOptions

MCQOPTIONS

1.	. 8x² + 6x = 5 . 12y² 22y + 8 = 0
A.	1
B.	2
C.	3
D.	4
E.	5
Answer» D. 4

Discussion

No Comment Found

Related MCQs

If x<sup>2</sup> - 3x + 1 = 0, find the value of x + 1/x,
If one of the roots of quadratic equation 7y<sup>2</sup> - 50y + k = 0 is 7, then what is the value of k ?
If x = <span style="text-decoration:overline"> <span style="text-decoration:overline">(5 + 1)</span>/ <span style="text-decoration:overline">(5 - 1)</span></span>, then x<sup>2</sup> - x - 1 is equal to
For what value of k, the equation x<sup>2</sup> + 2(k - 4) x + 2k = 0 has equal roots ?
Consider the equation <b>px<sup>2</sup> + qx + r = 0</b>, where <b>p, q, r</b> are real. The roots are equal in magnitude but opposite in sign when :
Find the value of <b>k</b> so that the sum of the roots of the equation <b>3x<sup>2</sup> + (2x + 1)x - k - 5 = 0 </b>is equal to the product of the roots :
The roots of the equation <b>4x - 3 2<sup>x</sup> 2<sup>2</sup> + 32 = 0</b> would include :
If <b> and </b> are the roots of the equation <b>x<sup>2</sup> - 3 x + <sup>2</sup> = 0,</b><br><table><tr><td rowspan="2">find <b> </b> if <b> <sup>2</sup> + <sup>2</sup> =</b></td><td style="border-bottom:1px solid #000000;vertical-align:bottom;padding-bottom:2px;"><center>7</center></td></tr><tr><td><center>4</center></td></tr></table>
The value of <b>k</b> for which the roots <b> , </b> of the equation : <b>x<sup>2</sup> 6x + k = 0</b> satisfy the relation <b>3 + 2 = 20</b>, is
If <b> , </b> are the roots of the equation <b>x<sup>2</sup> + kx + 12 = 0 </b> such that <b> = 1</b>, the value of <b>k</b> is